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midpoint
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critical f(x)=(x^2)/(x-2)critical points domain of 1/(x^2-2)domain perpendicular 3x+4y=5,\at ((-2,4)/7)perpendicular inverse of f(x)=x^2+11inverse inverse of log_{4}(x^3+2)inverse
Frequently Asked Questions (FAQ)
What is the midpoint (-1,2),(1,-2) ?
The midpoint (-1,2),(1,-2) is (0,0)