What is the extreme f(x)=(-x^6+6x)/(10) ?

The extreme f(x)=(-x^6+6x)/(10) is Maximum(1, 1/2)

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extreme f(x)=(-x^6+6x)/(10)

extreme points

f (x) = \frac{- x ^{6} + 6 x}{10}

Maximum (1, \frac{1}{2})

Solution steps

f^{'} (x) = \frac{3 ( - x ^{5} + 1 )}{5}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

\frac{- x ^{6} + 6 x}{10} : \frac{1}{2}

Maximum (1, \frac{1}{2})

\frac{5 x + 1}{x - 3}

f (x) = 2 tan (t - \frac{π}{2})

y = 5 x

f (x) = 3 x - 5

What is the extreme f(x)=(-x^6+6x)/(10) ?
The extreme f(x)=(-x^6+6x)/(10) is Maximum(1, 1/2)