What is the perpendicular y= 3/2 x-3/2 ,(-3,8) ?

The perpendicular y= 3/2 x-3/2 ,(-3,8) is y=-2/3 x+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y= 3/2 x-3/2 ,(-3,8)

perpendicular

y = \frac{3}{2} x - \frac{3}{2}, (- 3, 8)

y = - \frac{2}{3} x + 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{2} x - \frac{3}{2}

that passes through

(- 3, 8)

Find the slope of

y = \frac{3}{2} x - \frac{3}{2} : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(- 3, 8) : y = - \frac{2}{3} x + 6

y = - \frac{2}{3} x + 6

f (x) = x - 9 + 4

3 x + y = 14

1.5 cos (\frac{π ( x - 3 )}{26}) + 6.5

f (x) = (x + 7)^{3} + 2

f (x) = x^{2} + 1

What is the perpendicular y= 3/2 x-3/2 ,(-3,8) ?
The perpendicular y= 3/2 x-3/2 ,(-3,8) is y=-2/3 x+6