en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of-2x^2+8x-5

Solution

range

- 2 x^{2} + 8 x - 5

Solution

f (x) \leq 3

+1

Interval Notation

(- \infty, 3]

Solution steps

Vertex of

- 2 x^{2} + 8 x - 5 :

Maximum

(2, 3)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (2, 3)

f (x) \leq 3

Popular Examples

inflection (x-2)/(sqrt(x^2+1))inflection points

\frac{x - 2}{x ^{2} + 1}

domain of f(x)=sqrt(6x-30)domain

f (x) = 6 x - 30

domain of 2sqrt(x)+1 domain

2 x + 1

inverse of f(x)=(x+2)^5+2 inverse

f (x) = (x + 2)^{5} + 2

periodicity of f(x)=cos((8pi)/(31))periodicity

f (x) = cos (\frac{8 π}{31})

Frequently Asked Questions (FAQ)

What is the range of-2x^2+8x-5 ?
The range of-2x^2+8x-5 is f(x)<= 3