What is the critical x^2ln(x/6) ?

The critical x^2ln(x/6) is x= 6/(sqrt(e))

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critical x^2ln(x/6)

critical points

x^{2} ln (\frac{x}{6})

x = \frac{6}{e}

Solution steps

x^{2} ln (\frac{x}{6})

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{6}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} ln (\frac{x}{6}) : x > 0

x^{2} ln (\frac{x}{6})

is not defined at

x = 0

, therefore:

x = \frac{6}{e}

f (x) = x^{2} - 8 x + 12

f (x) = \frac{x}{x - 20}

f (x) = 2 x - tan (x)

f (x) = \frac{5}{x} + 4

y = \frac{5 x}{2 x + 3}