What is the inflection f(x)=4x^3-6x^2+7x-2 ?

The inflection f(x)=4x^3-6x^2+7x-2 is (1/2 , 1/2)

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inflection f(x)=4x^3-6x^2+7x-2

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 7 x - 2

(\frac{1}{2}, \frac{1}{2})

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 7 x - 2 : \frac{1}{2}

(\frac{1}{2}, \frac{1}{2})

4 t^{2}

f (x) = \frac{8 x - 26}{6} = x - 3

\frac{1}{2} x + 5 - 3

f (x) = - x^{3} + 3 x^{2} + 1

2 + 9 x

What is the inflection f(x)=4x^3-6x^2+7x-2 ?
The inflection f(x)=4x^3-6x^2+7x-2 is (1/2 , 1/2)