What is the range of (3+3x)/(x-2) ?

The range of (3+3x)/(x-2) is f(x) 3

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range of (3+3x)/(x-2)

range

\frac{3 + 3 x}{x - 2}

f (x) < 3 or f (x) > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3 + 3 x}{x - 2}

Inverse of

\frac{3 + 3 x}{x - 2} : \frac{3 + 2 x}{x - 3}

\frac{3 + 2 x}{x - 3}

Find the domain of each inverse function

Domain of

\frac{3 + 2 x}{x - 3} : x < 3 or x > 3

Combine the intervals

f (x) < 3 or f (x) > 3

- 5 cos (\frac{x}{3} + \frac{π}{2}) - 4

f (x) = - 3 x + 10

3 x - y = 7

f (x) = \frac{- 2}{5} x + 3

f (x) = \frac{- x + 17}{7}

What is the range of (3+3x)/(x-2) ?
The range of (3+3x)/(x-2) is f(x)<3\lor f(x)>3