What is the domain of f(x)=sqrt((x-1)/(x^2-9)) ?

The domain of f(x)=sqrt((x-1)/(x^2-9)) is -3 3

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domain of f(x)=sqrt((x-1)/(x^2-9))

domain

f (x) = \frac{x - 1}{x ^{2} - 9}

- 3 < x \leq 1 or x > 3

Interval Notation

(- 3, 1] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 3 < x \leq 1 or x > 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x \leq 1 or x > 3

f (x) = 2 x^{2} - 5 x + 1

\frac{2}{3 - x}

y = - 11 x

f (x) = x^{3} - 3 x^{2} - 9 x + 2

8 x - 4

What is the domain of f(x)=sqrt((x-1)/(x^2-9)) ?
The domain of f(x)=sqrt((x-1)/(x^2-9)) is -3<x<= 1\lor x>3