What is the line (-3/5 ,-11/3),(11/2 , 7/4) ?

The line (-3/5 ,-11/3),(11/2 , 7/4) is y= 325/366 x-1147/366

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line (-3/5 ,-11/3),(11/2 , 7/4)

line

(- \frac{3}{5}, - \frac{11}{3}), (\frac{11}{2}, \frac{7}{4})

y = \frac{325}{366} x - \frac{1147}{366}

Solution steps

Find the line

y = mx + b

passing through

(- \frac{3}{5}, - \frac{11}{3})

(\frac{11}{2}, \frac{7}{4})

Compute the slope

(- \frac{3}{5}, - \frac{11}{3}), (\frac{11}{2}, \frac{7}{4}) : m = \frac{325}{366}

Compute the

y

intercept:

b = - \frac{1147}{366}

Construct the line equation

y = mx + b

where

m = \frac{325}{366}

and

b = - \frac{1147}{366}

y = \frac{325}{366} x - \frac{1147}{366}

\frac{1 - 5 x}{4 + x}

f (x) = \frac{x ^{2} - x - 2}{- x ^{2} - 4 x - 4}

f (x) = x + 8

f (x) = 0.05 x + 20 + \frac{125}{x}

y = 1. 5^{x} + 4

What is the line (-3/5 ,-11/3),(11/2 , 7/4) ?
The line (-3/5 ,-11/3),(11/2 , 7/4) is y= 325/366 x-1147/366