What is the asymptotes of y=log_{6}(x-3)+1 ?

The asymptotes of y=log_{6}(x-3)+1 is Vertical: x=3

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asymptotes of y=log_{6}(x-3)+1

asymptotes

y = lo g_{6} (x - 3) + 1

Vertical : x = 3

Solution steps

Vertical asymptotes of

lo g_{6} (x - 3) + 1 : x = 3

Horizontal Asymptotes of

lo g_{6} (x - 3) + 1 :

None

Slant Asymptotes of

lo g_{6} (x - 3) + 1 :

None

Vertical : x = 3

\frac{x}{x + 1}

m = - 6, (7, 8)

sin (x) + 6

f (x) = \frac{x - 2}{( x - 2 ) ^{2}}

y = 18 x + 2, (1, - 5)

What is the asymptotes of y=log_{6}(x-3)+1 ?
The asymptotes of y=log_{6}(x-3)+1 is Vertical: x=3