What is the domain of (sqrt(x))/(3x^2+2x-1) ?

The domain of (sqrt(x))/(3x^2+2x-1) is 0 1/3

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domain of (sqrt(x))/(3x^2+2x-1)

domain

\frac{x}{3 x ^{2} + 2 x - 1}

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

[0, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{3}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

f (x) = 10 x^{3} + 9

x^{2} ln (x)

x^{2} - 2 x

f (x) = \frac{7}{x - 1}

y = (x - 2)^{2}

What is the domain of (sqrt(x))/(3x^2+2x-1) ?
The domain of (sqrt(x))/(3x^2+2x-1) is 0<= x< 1/3 \lor x> 1/3