What is the critical f(x)=sin^2(x) ?

The critical f(x)=sin^2(x) is x=pin,x= pi/2+pin

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critical f(x)=sin^2(x)

critical points

f (x) = sin^{2} (x)

x = πn, x = \frac{π}{2} + πn

Solution steps

sin^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = πn, x = \frac{π}{2} + πn

Identify critical points not in

f (x)

domain

Domain of

sin^{2} (x) : - \infty < x < \infty

All critical points are in domain

x = πn, x = \frac{π}{2} + πn

f (x) = e^{2 x - 3}

f (x) = \frac{x - 2}{x ^{3} - 36 x}

\frac{1}{x - 4}

f (x) = \frac{x - 3}{4}

y = x^{2} - 2 x - 8

What is the critical f(x)=sin^2(x) ?
The critical f(x)=sin^2(x) is x=pin,x= pi/2+pin