What is the inverse of f(x)=0.9^{-188.5+x}+105 ?

The inverse of f(x)=0.9^{-188.5+x}+105 is (ln(x-105))/(ln(0.9))+188.5

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inverse of f(x)=0.9^{-188.5+x}+105

inverse

f (x) = 0. 9^{- 188.5 + x} + 105

\frac{ln ( x - 105 )}{ln ( 0.9 )} + 188.5

Solution steps

y = 0. 9^{- 188.5 + x} + 105

Replace

x

with

y

x = 0. 9^{- 188.5 + y} + 105

Solve for

y, x = 0. 9^{- 188.5 + y} + 105

\frac{ln ( x - 105 )}{ln ( 0.9 )} + 188.5

y = 2 x - 3

y = \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

f (x) = \frac{x + 5}{x ^{3} + 27}

f (x) = 4 x - 10, x > 2

y = 4 x^{2} - 56 x + 204

What is the inverse of f(x)=0.9^{-188.5+x}+105 ?
The inverse of f(x)=0.9^{-188.5+x}+105 is (ln(x-105))/(ln(0.9))+188.5