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Popular >

distance (6,1),(2,-3)

Solution

distance

(6, 1), (2, - 3)

Solution

42

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(6, 1)

and

(2, - 3)

is

= (2 - 6)^{2} + (- 3 - 1)^{2}

Simplify

= 42

Popular Examples

perpendicular y=-2x-4 perpendicular

y = - 2 x - 4

domain of f(x)=((1))/((|x^{(2))-4|)}domain

f (x) = \frac{( 1 )}{( x ^{(2)} - 4 )}

range of x^2+2x+1 range

x^{2} + 2 x + 1

range of f(x)=(x+3)/(x+6)range

f (x) = \frac{x + 3}{x + 6}

inverse of f(x)=sqrt(7x)inverse

f (x) = 7 x

Frequently Asked Questions (FAQ)

What is the distance (6,1),(2,-3) ?
The distance (6,1),(2,-3) is 4sqrt(2)