What is the inverse of f(x)=sqrt(x^2+3x) ?

The inverse of f(x)=sqrt(x^2+3x) is (-3+sqrt(9+4x^2))/2 ,(-3-sqrt(9+4x^2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(x^2+3x)

inverse

f (x) = x^{2} + 3 x

\frac{- 3 + 9 + 4 x ^{2}}{2}, \frac{- 3 - 9 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 3 x

Replace

x

with

y

x = y^{2} + 3 y

Solve for

y, x = y^{2} + 3 y

\frac{- 3 + 9 + 4 x ^{2}}{2}, \frac{- 3 - 9 + 4 x ^{2}}{2}

1 + 3.22 ln (34)

f (x) = 2 x^{3} - x^{2} - 4 x + 10

f (x) = \frac{x + 1}{x - 1}

43 x^{3} - 48 x

f (x) = \frac{( 2 + x )}{x}

What is the inverse of f(x)=sqrt(x^2+3x) ?
The inverse of f(x)=sqrt(x^2+3x) is (-3+sqrt(9+4x^2))/2 ,(-3-sqrt(9+4x^2))/2