What is the domain of sqrt((4-x^2)/(x+1)) ?

The domain of sqrt((4-x^2)/(x+1)) is x<=-2\lor-1<x<= 2

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domain of sqrt((4-x^2)/(x+1))

domain

\frac{4 - x ^{2}}{x + 1}

x \leq - 2 or - 1 < x \leq 2

Interval Notation

(- \infty, - 2] \cup (- 1, 2]

Solution steps

Find non-negative values for radicals:

x \leq - 2 or - 1 < x \leq 2

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x \leq - 2 or - 1 < x \leq 2

- 15 - x = - 5 y

f (x) = 6 + lo g_{2} (x)

\frac{1}{2 ^{5}}

f (x) = \frac{x + 4}{x ^{2} - 4}

\frac{x}{1 + x ^{2}}

What is the domain of sqrt((4-x^2)/(x+1)) ?
The domain of sqrt((4-x^2)/(x+1)) is x<=-2\lor-1<x<= 2