What is the extreme f(x)=6x^4-36x^2 ?

The extreme f(x)=6x^4-36x^2 is Minimum(-sqrt(3),-54),Maximum(0,0),Minimum(sqrt(3),-54)

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extreme f(x)=6x^4-36x^2

extreme points

f (x) = 6 x^{4} - 36 x^{2}

Minimum (- 3, - 54), Maximum (0, 0), Minimum (3, - 54)

Solution steps

f^{'} (x) = 24 x^{3} - 72 x

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

6 x^{4} - 36 x^{2} : - 54

Minimum (- 3, - 54)

Plug

x = 0

into

6 x^{4} - 36 x^{2} : 0

Maximum (0, 0)

Plug

x = 3

into

6 x^{4} - 36 x^{2} : - 54

Minimum (3, - 54)

Minimum (- 3, - 54), Maximum (0, 0), Minimum (3, - 54)

f (x) = \frac{x ( cos ( 4 x ) - x ^{3} )}{sin ( 2 x ) - 3}

y = 5 x - 13

1 + x^{2}

x - 6

f (x) = 2 (x - 1)^{3} + 5

What is the extreme f(x)=6x^4-36x^2 ?
The extreme f(x)=6x^4-36x^2 is Minimum(-sqrt(3),-54),Maximum(0,0),Minimum(sqrt(3),-54)