What is the domain of f(x)= 1/(x-3)+2 ?

The domain of f(x)= 1/(x-3)+2 is x 3

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domain of f(x)= 1/(x-3)+2

domain

f (x) = \frac{1}{x - 3} + 2

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = \frac{- 3}{12 - x - x ^{2}}

f (x) = ln (1 + x)

f (x) = e^{4 x}

f (x) = ln (x - 1)

y = 3 x + 4

What is the domain of f(x)= 1/(x-3)+2 ?
The domain of f(x)= 1/(x-3)+2 is x<3\lor x>3