What is the critical f(x)=(x^3-8)^4 ?

The critical f(x)=(x^3-8)^4 is x=0,x=2

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critical f(x)=(x^3-8)^4

critical points

f (x) = (x^{3} - 8)^{4}

x = 0, x = 2

Solution steps

(x^{3} - 8)^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

(x^{3} - 8)^{4} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 2

12 x^{3} - 35

f (x) = tan (\frac{1}{2} x + π)

(6, - 1), (- 24, 19)

y = x - 6

\frac{( x + 3 )}{x + 4}