What is the domain of f(x)= 2/(sqrt(x-3)-1) ?

The domain of f(x)= 2/(sqrt(x-3)-1) is 3 4

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domain of f(x)= 2/(sqrt(x-3)-1)

domain

f (x) = \frac{2}{x - 3 - 1}

3 \leq x < 4 or x > 4

Interval Notation

[3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

3 \leq x < 4 or x > 4

\frac{sin ( 2 x )}{x + tan ( 8 x )}

y = 5 x^{5} - 7 x^{3}

f (x) = x + 2 - 5

4 x + 2 y = 20

f (x) = \frac{x ^{2} - 36}{x - 6}

What is the domain of f(x)= 2/(sqrt(x-3)-1) ?
The domain of f(x)= 2/(sqrt(x-3)-1) is 3<= x<4\lor x>4