What is the domain of f(x)=sqrt(x^2-5) ?

The domain of f(x)=sqrt(x^2-5) is x = sqrt(5)

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domain of f(x)=sqrt(x^2-5)

domain

f (x) = x^{2} - 5

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

The function domain

x \leq - 5 or x \geq 5

f (x) = \frac{( 2 x + 3 )}{4}

x^{2} - 2 x + 5

x^{3} + x

f (x) = (x + 1)^{3} - 4

f (x) = \frac{7}{x}

What is the domain of f(x)=sqrt(x^2-5) ?
The domain of f(x)=sqrt(x^2-5) is x<=-sqrt(5)\lor x>= sqrt(5)