What is the extreme f(x)=xsqrt(x+1) ?

The extreme f(x)=xsqrt(x+1) is Maximum(-1,0),Minimum(-2/3 ,-2/(3sqrt(3)))

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extreme f(x)=xsqrt(x+1)

extreme points

f (x) = x x + 1

Maximum (- 1, 0), Minimum (- \frac{2}{3}, - \frac{2}{3 3})

Solution steps

f^{'} (x) = \frac{3 x + 2}{2 x + 1}

Find intervals:

Decreasing

: - 1 < x < - \frac{2}{3},

Increasing

: - \frac{2}{3} < x < \infty

Plug

x = - 1

into

x x + 1 : 0

Maximum (- 1, 0)

Plug

x = - \frac{2}{3}

into

x x + 1 : - \frac{2}{3 3}

Minimum (- \frac{2}{3}, - \frac{2}{3 3})

Maximum (- 1, 0), Minimum (- \frac{2}{3}, - \frac{2}{3 3})

x^{2} - 8 x + 7

f (x) = x 64 - x^{2}

f (x) = \frac{( x ^{2} - 1 )}{( 2 x )}

f (x) = 7 x

y = x - 8

What is the extreme f(x)=xsqrt(x+1) ?
The extreme f(x)=xsqrt(x+1) is Maximum(-1,0),Minimum(-2/3 ,-2/(3sqrt(3)))