What is the inverse of f(x)=(2x^3-6)/9 ?

The inverse of f(x)=(2x^3-6)/9 is cube root of (9x+6)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(2x^3-6)/9

inverse

f (x) = \frac{2 x ^{3} - 6}{9}

Solution steps

y = \frac{2 x ^{3} - 6}{9}

Replace

x

with

y

x = \frac{2 y ^{3} - 6}{9}

Solve for

y, x = \frac{2 y ^{3} - 6}{9}

f (x) = \frac{x + 7}{x - 5}

f (x) = 2 (y - 1) (y - 2) (y - 3)

3 sin (\frac{2 π θ}{5})

\frac{x ^{2} - x - 12}{2 x - 8}

(- 2, 1), (4, 9)

What is the inverse of f(x)=(2x^3-6)/9 ?
The inverse of f(x)=(2x^3-6)/9 is cube root of (9x+6)/2