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Popular >

range of f(x)=-x^2+8x

Solution

range

f (x) = - x^{2} + 8 x

Solution

f (x) \leq 16

+1

Interval Notation

(- \infty, 16]

Solution steps

Vertex of

- x^{2} + 8 x :

Maximum

(4, 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (4, 16)

f (x) \leq 16

Popular Examples

intercepts of f(x)=6(x+7)-5 intercepts

f (x) = 6 (x + 7) - 5

range of f(x)=6-(x+2)^2 range

f (x) = 6 - (x + 2)^{2}

inverse of (-(3))/((x-1)-1)inverse

\frac{- ( 3 )}{( x - 1 ) - 1}

domain of f(x)=sqrt(40-4x)domain

f (x) = 40 - 4 x

parallel y=-5/3 x-3 parallel

y = - \frac{5}{3} x - 3

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2+8x ?
The range of f(x)=-x^2+8x is f(x)<= 16