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Popular >

distance (8,6),(3,6)

Solution

distance

(8, 6), (3, 6)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(8, 6)

and

(3, 6)

is

= (3 - 8)^{2} + (6 - 6)^{2}

Simplify

= 5

Popular Examples

inflection f(x)=x^3-3x+4 inflection points

f (x) = x^{3} - 3 x + 4

inverse of f(x)=2sqrt(x-5)+1 inverse

f (x) = 2 x - 5 + 1

parity f(x)=-2x^2-2 parity

f (x) = - 2 x^{2} - 2

midpoint (8q,8q),(2q,3q)midpoint

(8 q, 8 q), (2 q, 3 q)

monotone f(x)=3(1/4)^{x+5}monotone intervals

f (x) = 3 (\frac{1}{4})^{x + 5}

Frequently Asked Questions (FAQ)

What is the distance (8,6),(3,6) ?
The distance (8,6),(3,6) is 5