What is the domain of f(x)=(sqrt(x+2))/x ?

The domain of f(x)=(sqrt(x+2))/x is -2 0

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domain of f(x)=(sqrt(x+2))/x

domain

f (x) = \frac{x + 2}{x}

- 2 \leq x < 0 or x > 0

Interval Notation

[- 2, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 2 \leq x < 0 or x > 0

f (x) = arctan (ln (e^{t a n (x^{2})}))

y = \frac{1}{2} x - 4

f (x) = 13 x^{4} - 78 x^{2}

cos (x)

(- 4, 3), (8, - 1)

What is the domain of f(x)=(sqrt(x+2))/x ?
The domain of f(x)=(sqrt(x+2))/x is -2<= x<0\lor x>0