What is the extreme f(x)=x^3-6x^2+9x+5 ?

The extreme f(x)=x^3-6x^2+9x+5 is Maximum(1,9),Minimum(3,5)

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extreme f(x)=x^3-6x^2+9x+5

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 5

Maximum (1, 9), Minimum (3, 5)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 5 : 9

Maximum (1, 9)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 5 : 5

Minimum (3, 5)

Maximum (1, 9), Minimum (3, 5)

\frac{x ^{2} - 6 x + 8}{x ^{2} - 16}

f (n) = \frac{1}{9} n - \frac{4}{9}

f (x) = 2 x^{3} - 3 x^{2} - 36 x

f (x) = 3 x + 3

f (x) = - 1

What is the extreme f(x)=x^3-6x^2+9x+5 ?
The extreme f(x)=x^3-6x^2+9x+5 is Maximum(1,9),Minimum(3,5)