What is the domain of sqrt((-x^2+4)(x+1)) ?

The domain of sqrt((-x^2+4)(x+1)) is x<=-2\lor-1<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt((-x^2+4)(x+1))

domain

(- x^{2} + 4) (x + 1)

x \leq - 2 or - 1 \leq x \leq 2

Interval Notation

(- \infty, - 2] \cup [- 1, 2]

Solution steps

Find non-negative values for radicals:

x \leq - 2 or - 1 \leq x \leq 2

The function domain

x \leq - 2 or - 1 \leq x \leq 2

4 x - 5 y = 20

(- 3.1, - 2.8), (- 4.92, - 3.3)

f (x) = x^{3} + 3 x^{2} + 3 x + 2

f (x) = 2 x^{3} + 4 x

2 x - y = - 2

What is the domain of sqrt((-x^2+4)(x+1)) ?
The domain of sqrt((-x^2+4)(x+1)) is x<=-2\lor-1<= x<= 2