What is the critical f(x)=(x+2)^5(x-3)^4 ?

The critical f(x)=(x+2)^5(x-3)^4 is x=-2,x= 7/9 ,x=3

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critical f(x)=(x+2)^5(x-3)^4

critical points

f (x) = (x + 2)^{5} (x - 3)^{4}

x = - 2, x = \frac{7}{9}, x = 3

Solution steps

(x + 2)^{5} (x - 3)^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = \frac{7}{9}, x = 3

Identify critical points not in

f (x)

domain

Domain of

(x + 2)^{5} (x - 3)^{4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = \frac{7}{9}, x = 3

(- 3.2) (6)

\frac{- 3 x}{x ^{2} - 1}

5 x + y = - 3

f (x) = 8 x^{\frac{1}{3}}

y = x^{2} - 8 x + 15

What is the critical f(x)=(x+2)^5(x-3)^4 ?
The critical f(x)=(x+2)^5(x-3)^4 is x=-2,x= 7/9 ,x=3