What is the domain of f(x)=(t^2-1)/(t+1) ?

The domain of f(x)=(t^2-1)/(t+1) is t -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(t^2-1)/(t+1)

domain

f (x) = \frac{t ^{2} - 1}{t + 1}

t < - 1 or t > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

t = - 1

The function domain

t < - 1 or t > - 1

f (x) = x^{2} + 2 x - 15

f (x) = \frac{2 x - 1}{2 x ^{4} + x ^{3} - 6 x ^{2}}

f (x) = \frac{- x ^{2} - 4 x + 5}{4 x - 4}

f (x) = \frac{x}{3 x - 4}

\frac{y}{y - 6} + \frac{15}{y + 6}

What is the domain of f(x)=(t^2-1)/(t+1) ?
The domain of f(x)=(t^2-1)/(t+1) is t<-1\lor t>-1