What is the inverse of f(x)=((-x+1))/((x-3)) ?

The inverse of f(x)=((-x+1))/((x-3)) is (1+3x)/(x+1)

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inverse of f(x)=((-x+1))/((x-3))

inverse

f (x) = \frac{( - x + 1 )}{( x - 3 )}

\frac{1 + 3 x}{x + 1}

Solution steps

y = \frac{- x + 1}{x - 3}

Replace

x

with

y

x = \frac{- y + 1}{y - 3}

Solve for

y, x = \frac{- y + 1}{y - 3}

\frac{1 + 3 x}{x + 1}

f (x) = \frac{8 x ^{2}}{x ^{4} + 16}

f (x) = x^{5}

(- 3, 6), (- 6, - 2)

2.5 t + 11.5

y = - 3 x + 5

What is the inverse of f(x)=((-x+1))/((x-3)) ?
The inverse of f(x)=((-x+1))/((x-3)) is (1+3x)/(x+1)