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Popular >

midpoint (0,-4),(10,-3)

Solution

midpoint

(0, - 4), (10, - 3)

Solution

(5, - \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 4), (x_{2}, y_{2}) = (10, - 3)

= (\frac{10 + 0}{2}, \frac{- 3 - 4}{2})

Refine

= (5, - \frac{7}{2})

Popular Examples

inverse of f(x)=(x-8)^{1/2}inverse

f (x) = (x - 8)^{\frac{1}{2}}

inverse of f(x)=3(x-4)+10 inverse

f (x) = 3 (x - 4) + 10

inverse of f(x)= 1/3 x^3-6 inverse

f (x) = \frac{1}{3} x^{3} - 6

domain of-(21)/((5+t)^2)domain

- \frac{21}{( 5 + t ) ^{2}}

intercepts of f(x)=(-2x-9)/(4x-19)intercepts

f (x) = \frac{- 2 x - 9}{4 x - 19}

Frequently Asked Questions (FAQ)

What is the midpoint (0,-4),(10,-3) ?
The midpoint (0,-4),(10,-3) is (5,-7/2)