What is the domain of f(x)=(sqrt(4+x))/(8-x) ?

The domain of f(x)=(sqrt(4+x))/(8-x) is -4 8

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domain of f(x)=(sqrt(4+x))/(8-x)

domain

f (x) = \frac{4 + x}{8 - x}

- 4 \leq x < 8 or x > 8

Interval Notation

[- 4, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 4 \leq x < 8 or x > 8

x^{2} + 2 x - 3

f (x) = \frac{4}{x ^{2} - 2 x}

f (x) = 18500 (0.49 - x^{2})

(15, - 17), (- 20, - 5)

(0, 7), (- 2, - 1)

What is the domain of f(x)=(sqrt(4+x))/(8-x) ?
The domain of f(x)=(sqrt(4+x))/(8-x) is -4<= x<8\lor x>8