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Popular >

inverse of y=x^2+x

Solution

inverse

y = x^{2} + x

Solution

\frac{- 1 + 1 + 4 x}{2}, \frac{- 1 - 1 + 4 x}{2}

Solution steps

y = x^{2} + x

Replace

x

with

y

x = y^{2} + y

Solve for

y, x = y^{2} + y

\frac{- 1 + 1 + 4 x}{2}, \frac{- 1 - 1 + 4 x}{2}

Popular Examples

domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x))domain

f (x) = \frac{\frac{3}{2}}{2 \frac{5}{2} + \frac{3}{2} x}

range of x-5 range

x - 5

critical f(x)=-(x^2)/2-3x-1/2 critical points

f (x) = - \frac{x ^{2}}{2} - 3 x - \frac{1}{2}

asymptotes of y=(2e^x)/(e^x-5)asymptotes

y = \frac{2 e ^{x}}{e ^{x} - 5}

domain of f(x)=(x^2+2)/(x+4)domain

f (x) = \frac{x ^{2} + 2}{x + 4}

Frequently Asked Questions (FAQ)

What is the inverse of y=x^2+x ?
The inverse of y=x^2+x is (-1+sqrt(1+4x))/2 ,(-1-sqrt(1+4x))/2