What is the asymptotes of y=(x^2-9)/(x^2+5x) ?

The asymptotes of y=(x^2-9)/(x^2+5x) is Vertical: x=-5,x=0,Horizontal: y=1

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asymptotes of y=(x^2-9)/(x^2+5x)

asymptotes

y = \frac{x ^{2} - 9}{x ^{2} + 5 x}

Vertical : x = - 5, x = 0, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{x ^{2} + 5 x} : x = - 5, x = 0

Horizontal Asymptotes of

\frac{x ^{2} - 9}{x ^{2} + 5 x} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 9}{x ^{2} + 5 x} :

None

Vertical : x = - 5, x = 0, Horizontal : y = 1

y = - 3 x + 1

f (x) = \frac{5000}{x} - 300

4 x^{2} - 24 x + 34

f (x) = \frac{x ^{2}}{x ^{2} + 3}

f (x) = 20 - x

What is the asymptotes of y=(x^2-9)/(x^2+5x) ?
The asymptotes of y=(x^2-9)/(x^2+5x) is Vertical: x=-5,x=0,Horizontal: y=1