What is the domain of f(x)= 1/(2x^2-18) ?

The domain of f(x)= 1/(2x^2-18) is x 3

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domain of f(x)= 1/(2x^2-18)

domain

f (x) = \frac{1}{2 x ^{2} - 18}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

(- 3.5, - 1), (16, - 10)

f (x) = \frac{( 1 + x ^{4} )}{( x ^{2} - x ^{4} )}

\frac{( x - 1 )}{( x ^{2} + 4 )}

f (x) = - 19 x + 13

f (x) = x - 2 y = 2

What is the domain of f(x)= 1/(2x^2-18) ?
The domain of f(x)= 1/(2x^2-18) is x<-3\lor-3<x<3\lor x>3