What is the inverse of f(x)=2x^2-8x+3 ?

The inverse of f(x)=2x^2-8x+3 is (8+sqrt(8x+40))/4 ,(8-sqrt(8x+40))/4

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inverse of f(x)=2x^2-8x+3

inverse

f (x) = 2 x^{2} - 8 x + 3

\frac{8 + 8 x + 40}{4}, \frac{8 - 8 x + 40}{4}

Solution steps

y = 2 x^{2} - 8 x + 3

Replace

x

with

y

x = 2 y^{2} - 8 y + 3

Solve for

y, x = 2 y^{2} - 8 y + 3

\frac{8 + 8 x + 40}{4}, \frac{8 - 8 x + 40}{4}

\frac{9}{x}

f (x) = 2 x^{2} - 4 x

(- 15, - 2), (- 6, - 4)

f (x) = 1 + 5 x + x^{2}

f (x) = x + 3 y = 6

What is the inverse of f(x)=2x^2-8x+3 ?
The inverse of f(x)=2x^2-8x+3 is (8+sqrt(8x+40))/4 ,(8-sqrt(8x+40))/4