What is the perpendicular y= 2/3 x-3,(6,-1) ?

The perpendicular y= 2/3 x-3,(6,-1) is y=-3/2 x+8

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perpendicular y= 2/3 x-3,(6,-1)

perpendicular

y = \frac{2}{3} x - 3, (6, - 1)

y = - \frac{3}{2} x + 8

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{2}{3} x - 3

that passes through

(6, - 1)

Find the slope of

y = \frac{2}{3} x - 3 : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(6, - 1) : y = - \frac{3}{2} x + 8

y = - \frac{3}{2} x + 8

f (x) = 5 tan (5 x)

f (x) = e^{2 x - 8}

x^{3} - x^{7}

f (x) = \frac{- 5}{x + 3}

2 x + 5 y = - 19

What is the perpendicular y= 2/3 x-3,(6,-1) ?
The perpendicular y= 2/3 x-3,(6,-1) is y=-3/2 x+8