What is the asymptotes of f(x)=(8x+36)/(10x-5) ?

The asymptotes of f(x)=(8x+36)/(10x-5) is Vertical: x= 1/2 ,Horizontal: y= 4/5

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asymptotes of f(x)=(8x+36)/(10x-5)

asymptotes

f (x) = \frac{8 x + 36}{10 x - 5}

Vertical : x = \frac{1}{2}, Horizontal : y = \frac{4}{5}

Solution steps

Vertical asymptotes of

\frac{8 x + 36}{10 x - 5} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{8 x + 36}{10 x - 5} : y = \frac{4}{5}

Slant Asymptotes of

\frac{8 x + 36}{10 x - 5} :

None

Vertical : x = \frac{1}{2}, Horizontal : y = \frac{4}{5}

lo g_{2} (x + 5) + 1

f (x) = 6 - 2 x

\frac{2 x}{x ^{2} + 4}

f (x) = (x - 10)^{2}

f (x) = y^{2} - 2 - y

What is the asymptotes of f(x)=(8x+36)/(10x-5) ?
The asymptotes of f(x)=(8x+36)/(10x-5) is Vertical: x= 1/2 ,Horizontal: y= 4/5