What is the inverse of f(x)=x^2-8x+16 ?

The inverse of f(x)=x^2-8x+16 is 4+sqrt(x),4-sqrt(x)

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inverse of f(x)=x^2-8x+16

inverse

f (x) = x^{2} - 8 x + 16

4 + x, 4 - x

Solution steps

y = x^{2} - 8 x + 16

Replace

x

with

y

x = y^{2} - 8 y + 16

Solve for

y, x = y^{2} - 8 y + 16

4 + x, 4 - x

f (x) = \frac{2 x ^{2} - x - 6}{x ^{2} + 9}

\frac{x ^{12}}{x ^{- 2}}

x^{3} (x + 5)^{2} + 5

cos (5 x)

4 x + 5

What is the inverse of f(x)=x^2-8x+16 ?
The inverse of f(x)=x^2-8x+16 is 4+sqrt(x),4-sqrt(x)