What is the critical x/(x^2+12x+32) ?

The critical x/(x^2+12x+32) is x=-4sqrt(2),x=4sqrt(2)

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critical x/(x^2+12x+32)

critical points

\frac{x}{x ^{2} + 12 x + 32}

x = - 42, x = 42

Solution steps

\frac{x}{x ^{2} + 12 x + 32}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 42, x = 42, x = - 8, x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 12 x + 32} : x < - 8 or - 8 < x < - 4 or x > - 4

\frac{x}{x ^{2} + 12 x + 32}

is not defined at

x = - 8, x = - 4

, therefore:

x = - 42, x = 42

5 x + 6 y = 7

\frac{x ^{2} - 1}{x - 1}

m = 2 (- 1.4)

f (x) = \frac{x + 1}{x}

3 - x - x^{2} - 1

What is the critical x/(x^2+12x+32) ?
The critical x/(x^2+12x+32) is x=-4sqrt(2),x=4sqrt(2)