What is the inverse of f(x)=ln(x^2)-9,x<= 0 ?

The inverse of f(x)=ln(x^2)-9,x<= 0 is sqrt(e^{x+9)},-sqrt(e^{x+9)}

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inverse of f(x)=ln(x^2)-9,x<= 0

inverse

f (x) = ln (x^{2}) - 9, x \leq 0

e^{x + 9}, - e^{x + 9}

Solution steps

y = ln (x^{2}) - 9

Replace

x

with

y

x = ln (y^{2}) - 9

Solve for

y, x = ln (y^{2}) - 9

e^{x + 9}, - e^{x + 9}

f (x) = - x - 1

f (x) = - tan (x + 5) - 4

12 x + 5 y = - 1

\frac{3}{x + 5}

What is the inverse of f(x)=ln(x^2)-9,x<= 0 ?
The inverse of f(x)=ln(x^2)-9,x<= 0 is sqrt(e^{x+9)},-sqrt(e^{x+9)}