What is the inverse of f(x)= 3/2 x^3+4 ?

The inverse of f(x)= 3/2 x^3+4 is cube root of (2x-8)/3

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inverse of f(x)= 3/2 x^3+4

inverse

f (x) = \frac{3}{2} x^{3} + 4

Solution steps

y = \frac{3}{2} x^{3} + 4

Replace

x

with

y

x = \frac{3}{2} y^{3} + 4

Solve for

y, x = \frac{3}{2} y^{3} + 4

f (x) = \frac{x}{x + 2}

f (x) = \frac{2 x}{x ^{2} + 1}

f (x) = \frac{x + 8}{x ^{2} - 64}

f (x) = \frac{2 x - 3}{x - 1}

sec^{3} (x) d x

What is the inverse of f(x)= 3/2 x^3+4 ?
The inverse of f(x)= 3/2 x^3+4 is cube root of (2x-8)/3