What is the domain of h(x)=(19)/(x^2-3x) ?

The domain of h(x)=(19)/(x^2-3x) is x 3

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domain of h(x)=(19)/(x^2-3x)

domain

h (x) = \frac{19}{x ^{2} - 3 x}

x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 0

The function domain

x < 0 or 0 < x < 3 or x > 3

\frac{9}{x}

\frac{x ^{3} + 4 x ^{2}}{7 x ^{2} - 2}

f (x) = sin (- π t)

f (x) = \frac{5}{x ^{2} + 2 x - 3}

\frac{( x + 1 ) ( x - 3 )}{x - 3}

What is the domain of h(x)=(19)/(x^2-3x) ?
The domain of h(x)=(19)/(x^2-3x) is x<0\lor 0<x<3\lor x>3