What is the domain of (x^3+4x^2)/(7x^2-2) ?

The domain of (x^3+4x^2)/(7x^2-2) is x sqrt(2/7)

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domain of (x^3+4x^2)/(7x^2-2)

domain

\frac{x ^{3} + 4 x ^{2}}{7 x ^{2} - 2}

x < - \frac{2}{7} or - \frac{2}{7} < x < \frac{2}{7} or x > \frac{2}{7}

Interval Notation

(- \infty, - \frac{2}{7}) \cup (- \frac{2}{7}, \frac{2}{7}) \cup (\frac{2}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{7}, x = - \frac{2}{7}

The function domain

x < - \frac{2}{7} or - \frac{2}{7} < x < \frac{2}{7} or x > \frac{2}{7}

f (x) = sin (- π t)

f (x) = \frac{5}{x ^{2} + 2 x - 3}

\frac{( x + 1 ) ( x - 3 )}{x - 3}

f (x) = x^{2} - 16

7 - x^{2}

What is the domain of (x^3+4x^2)/(7x^2-2) ?
The domain of (x^3+4x^2)/(7x^2-2) is x<-sqrt(2/7)\lor-sqrt(2/7)<x<sqrt(2/7)\lor x>sqrt(2/7)