What is the domain of f(x)=sqrt(1+x) ?

The domain of f(x)=sqrt(1+x) is x>=-1

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domain of f(x)=sqrt(1+x)

domain

f (x) = 1 + x

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = \frac{1}{5 + e ^{2 x}}

3 x^{4} - 15

f (x) = \frac{13 x ^{2}}{7 x ^{2} + 6}

y = \frac{1}{2} x + 2

f (x) = \frac{4 x}{x ^{2} + 81}