What is the critical f(x)=1+3/x+2/(x^2) ?

The critical f(x)=1+3/x+2/(x^2) is x=-4/3

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critical f(x)=1+3/x+2/(x^2)

critical points

f (x) = 1 + \frac{3}{x} + \frac{2}{x ^{2}}

x = - \frac{4}{3}

Solution steps

1 + \frac{3}{x} + \frac{2}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{4}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

1 + \frac{3}{x} + \frac{2}{x ^{2}} : x < 0 or x > 0

1 + \frac{3}{x} + \frac{2}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - \frac{4}{3}

f (x) = x^{2} + 5 x

2 x + 3 y = - 12

\frac{5}{x} + 6

f (v) = (2 v - 7)^{2}

What is the critical f(x)=1+3/x+2/(x^2) ?
The critical f(x)=1+3/x+2/(x^2) is x=-4/3