What is the range of sqrt(5/x+6) ?

The range of sqrt(5/x+6) is 0 sqrt(6)

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range of sqrt(5/x+6)

range

\frac{5}{x} + 6

0 \leq f (x) < 6 or f (x) > 6

Interval Notation

[0, 6) \cup (6, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{5}{x} + 6 : x \leq - \frac{5}{6} or x > 0

Extreme Points of

\frac{5}{x} + 6 :

None

Find the range for the interval

- \infty < x \leq - \frac{5}{6} : 0 \leq f (x) < 6

Find the range for the interval

0 < x < \infty : 6 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

0 \leq f (x) < 6 or f (x) > 6

0 \leq f (x) < 6 or f (x) > 6

f (v) = (2 v - 7)^{2}

(m, n), (0, 0)

(6, - 5), (3, 1)

f (x) = 2 x^{3} - 3 x^{2} - 72 x + 3

What is the range of sqrt(5/x+6) ?
The range of sqrt(5/x+6) is 0<= f(x)<sqrt(6)\lor f(x)>sqrt(6)