What is the extreme f(x)=2x^3-3x^2-72x+3 ?

The extreme f(x)=2x^3-3x^2-72x+3 is Maximum(-3,138),Minimum(4,-205)

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extreme f(x)=2x^3-3x^2-72x+3

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 72 x + 3

Maximum (- 3, 138), Minimum (4, - 205)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 72

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 3

into

2 x^{3} - 3 x^{2} - 72 x + 3 : 138

Maximum (- 3, 138)

Plug

x = 4

into

2 x^{3} - 3 x^{2} - 72 x + 3 : - 205

Minimum (4, - 205)

Maximum (- 3, 138), Minimum (4, - 205)

lo g_{3} (x + 6)

f (x) = \frac{6 ^{x}}{3}

f (x) = - 3 x^{2} - 24 x - 47

X^{3}

f (x) = \frac{8}{5 x - 7}

What is the extreme f(x)=2x^3-3x^2-72x+3 ?
The extreme f(x)=2x^3-3x^2-72x+3 is Maximum(-3,138),Minimum(4,-205)