What is the domain of f(x)= 6/(x^2+16)+6/(x^2-1) ?

The domain of f(x)= 6/(x^2+16)+6/(x^2-1) is x 1

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domain of f(x)= 6/(x^2+16)+6/(x^2-1)

domain

f (x) = \frac{6}{x ^{2} + 16} + \frac{6}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = x^{3} + 7 x^{2} - 3 x + 9

x^{3} - 27

(x + 1)^{2}

y = \frac{x - 2}{x + 2}

f (x) = \frac{x ^{2} + 4}{4 x - 4}

What is the domain of f(x)= 6/(x^2+16)+6/(x^2-1) ?
The domain of f(x)= 6/(x^2+16)+6/(x^2-1) is x<-1\lor-1<x<1\lor x>1